Science, asked by ItzurBeBe, 1 month ago

\boxed{\begin{array}{| c | c | c | c | c | c |}\\ \bf{∠ A } & \bf{ 0° } & \bf{30°} & \bf{45°} & \bf{60°} & \bf{90°}\\\\ \textsf{Sin\;∅} & 0 & \cfrac{1}{2} & \cfrac{1}{\sqrt{2}} & \cfrac{\sqrt{3}}{2} & 1 \\\\ \textsf{cos\;∅} & 1 & \cfrac{\sqrt{3}}{2} & \cfrac{1}{\sqrt{2}} & \cfrac{1}{2} & 0 \\\\ \textsf{tan\;∅} & 0 &\cfrac{1}{\sqrt{2}} &  1 & \sqrt{3} & \sf{N.D.} \\\\ \textsf{cosec\;∅} &\sf{N.D.}& 2 & \sqrt{2} & \cfrac{2}{\sqrt{3}} & 1 \\\\ \textsf{sec\;∅} & 1 & \cfrac{2}{\sqrt{3}} & \sqrt{2} & 2 & \sf{N.D.} \\\\ \textsf{cot\;∅} & \sf{N.D.} & \sqrt{3} & 1 & \cfrac{1}{\sqrt{3}} & 0 \\ \end{array}}

Answers

Answered by ItUrBaby
3

\huge\bold\pink{Answer}

\boxed{\begin{array}{| c | c | c | c | c | c |}\\ \bf{∠ A } & \bf{ 0° } & \bf{30°} & \bf{45°} & \bf{60°} & \bf{90°}\\\\ \textsf{Sin\;∅} & 0 & \cfrac{1}{2} & \cfrac{1}{\sqrt{2}} & \cfrac{\sqrt{3}}{2} & 1 \\\\ \textsf{cos\;∅} & 1 & \cfrac{\sqrt{3}}{2} & \cfrac{1}{\sqrt{2}} & \cfrac{1}{2} & 0 \\\\ \textsf{tan\;∅} & 0 &\cfrac{1}{\sqrt{2}} &  1 & \sqrt{3} & \sf{N.D.} \\\\ \textsf{cosec\;∅} &\sf{N.D.}& 2 & \sqrt{2} & \cfrac{2}{\sqrt{3}} & 1 \\\\ \textsf{sec\;∅} & 1 & \cfrac{2}{\sqrt{3}} & \sqrt{2} & 2 & \sf{N.D.} \\\\ \textsf{cot\;∅} & \sf{N.D.} & \sqrt{3} & 1 & \cfrac{1}{\sqrt{3}} & 0 \\ \end{array}}

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\huge\mathfrak\fcolorbox{Grey}{pink}{✪\: \: ItUrBaby\: \:✪}

Answered by Alone00160
1

Answer</p><p></p><p>\begin{gathered}\boxed{\begin{array}{| c | c | c | c | c | c |}\\ \bf{∠ A } &amp; \bf{ 0° } &amp; \bf{30°} &amp; \bf{45°} &amp; \bf{60°} &amp; \bf{90°}\\\\ \textsf{Sin\;∅} &amp; 0 &amp; \cfrac{1}{2} &amp; \cfrac{1}{\sqrt{2}} &amp; \cfrac{\sqrt{3}}{2} &amp; 1 \\\\ \textsf{cos\;∅} &amp; 1 &amp; \cfrac{\sqrt{3}}{2} &amp; \cfrac{1}{\sqrt{2}} &amp; \cfrac{1}{2} &amp; 0 \\\\ \textsf{tan\;∅} &amp; 0 &amp;\cfrac{1}{\sqrt{2}} &amp; 1 &amp; \sqrt{3} &amp; \sf{N.D.} \\\\ \textsf{cosec\;∅} &amp;\sf{N.D.}&amp; 2 &amp; \sqrt{2} &amp; \cfrac{2}{\sqrt{3}} &amp; 1 \\\\ \textsf{sec\;∅} &amp; 1 &amp; \cfrac{2}{\sqrt{3}} &amp; \sqrt{2} &amp; 2 &amp; \sf{N.D.} \\\\ \textsf{cot\;∅} &amp; \sf{N.D.} &amp; \sqrt{3} &amp; 1 &amp; \cfrac{1}{\sqrt{3}} &amp; 0 \\ \end{array}}\end{gathered}∠ASin∅cos∅tan∅cosec∅sec∅cot∅0°010N.D.1N.D.30°212321232345°2121122160°232133223190°10N.D.1N.D.0</p><p></p><p></p><p>

didi aapne mujhe agr pehchan liya toh mere ko innsta pr message krna --alone_00160 joker ki DP hogi

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