Math, asked by Anonymous, 1 month ago


{ \boxed{ \boxed{ \bold \red{Don't \:  try \:  to  \: spam}}}}



If 5% of families in Kolkata do not use gas as a fuel, what will be the probability of selecting 10 families in a random sample of 100 families who do not use gas as fuel ?


  \boxed{\sf Note:-}
☛ Quality and explained answer required 
☛ Spammers stay away. 
☛ Answer only if you know ​

Answers

Answered by MysticSohamS
10

Answer:

hey here is your answer

pls mark it as brainliest

Step-by-step explanation:

so here the total families in Kolkata=100

so out of 100 families 5% of families do noylt use gas as a fuel

thus then no of families who do not use gas as a fuel=(100-5% of 100)

=100-5

=95

thus n(S)=95

so here 10 families are to be selected our of 95 randomly who do not use gas as a fuel

so let A be the event so as to get 10 families who do not use gas as a fuel

so n(A)=10

now using

P(A)=n(A)/n(S)

=10/95

=2/19

so the probability of selecting 10 families in a random sample of 100 families who do not use gas as fuel is 2/19

hope it helped u a lot

I don't know is my answer ryt or wrong

not sure

Similar questions