Question

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$\boxed{μ = 0.05}$
Find Acceleration



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Answer 1

Explanation:

❑Given ➦

• μ = 0.05

• $\sf{V_1 = 30 \: ms}$

• $V_2 = 20 \: ms$

• $\sf{t_1 = 0 \: sec}$

• $\sf{t_2 = 2 \: sec}$

❑TO Find ➦

• Acceleration

Solution :-

$\sf{∆V = V_2 - V_1}$

$\sf{ \: \: \: \: \: = 30 - 20 }$

${\therefore{ { { {∆V = 10}}}}}$

$\boxed{ \boxed{ a = \frac{∆V }{t} }}$

$\sf{ \implies{a = \cancel\frac{10}{2} }} \\ \\ a = 5$

$\bold{ { \boxed{ \boxed{F = ma }}}}$

$\implies{ \sf{F =1000 \times 5}} \\ \\ \\ F = 5000 \: N$

$\sf{ \boxed{F_r = μN}} \\ \\ F_r = 0.05 \times 5000 \\ \\ \\ F_r = 250$

$\sf{ \boxed{F_net = F -F_r}} \\ \\ \\ \\ = 5000 - 250 \\ =4750$

Answer 2

Answer:

4750

hope it will help you!!!!!!!!!!!!!!