Question

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Solve this Using Compound Interest:-

P = 8000
R = 10%
n = 1 year
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Answer 1

Given:-

• P = 8000

• R = 10%

• n = 1 year

To Find:-

• Compound Interest

Solution:-

$A= p(1 + \frac{r}{100} ) {}^{t} \\ \\ \\ A = 8000(1 + \frac{5}{100} ) {}^{2} \\ \\ \\ A= 8000(1 + 0.05) {}^{2} \\ \\ \\ A= 8000(1.05) {}^{2} \\ \\ \\ = 8000 \times \frac{105}{100} \times \frac{105}{100} \\ \\ \\ A= 8000 \times \frac{21}{20} \times \frac{21}{20} \\ \\ \\ A= \frac{8000}{400} \times 21 \times 21 \\ \\ \\ A = 20 \times 441 \\ \\ \\ A =₹ \: 8820 \\ \\ \\ C. I = Amount - Principal \\ \\ = ₹ \: (8820 - 8000) \\ \\ = ₹820$

Answer 2

Answer:

820 rupees

Step-by-step explanation:

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