Question

$\boxed {\color{red}\huge \frak{ \star\: holla \: friends \: \star}} \\ \\ \frak {help \: me \: out - } \\ \\ \bf{if \: the \: zeroes \: of \: the \: polynomial} \\ \bf{ {x}^{3} - {3x }^{2} + x + 1 \: are \: a - b , a ,\: a + b. } \\ \\ \ \color{blue} \bf{please \: \frak{solve} \: this \: one} \\ \color{red} \huge \: i \: will \: mark \: \frak{you} \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{brainliest \frak{'s \: one}}$
,✍️✍️✍️✍️✍️✍️ let's do this fast

Answer 1

if a,a+b and a-b are zeros of p(x)
a+a+b+a-b=3/1
3a=3
a=1
and a(a+b)(a-b)=-1/1
a(a²-b²)=-1
1-b²=-1
-b²=-2
b²=2
b=√2
please mark it as brainliest

Answer 2

Yo!

Here's the answer!

If a,a+b and a-b are zeros of p(x)

then,a+a+b+a-b=3/1

3a=3

a=1

so, a(a+b)(a-b)=-1/1

a(a²-b²)=-1

1-b²=-1

-b²=-2

b²=2

b=√2

Hope that this helps you!

-TGA.