Math, asked by Anonymous, 6 months ago

\boxed{\fcolorbox{black}{pink}{Question:-}}

⟾Bela borrowed ₹25000 from a finance company to start her boutique at 20% per compounded Half-yearly. What amount of money will clear her debt after 1 ½ yrs.

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Answers

Answered by Auяoяà
30

\sf\red{⟾Given:}

  • P=₹25000
  • R=20%p.a.=10% half Yearly
  • T=1½years=3half years

\sf\pink{⟾To\:find:}

  • The amount of money that will clear her debt after 1½ yrs.

\sf\blue{⟾Solution:}

i}Interest 1=\frac{25000×10×1}{100}

=₹2500

Amount 1=25000+2500=₹27500

ii} Interest 2=\frac{27500×10×1}{100}

=₹2750

Amount 2=27500+2750=₹30250

iii} Interest 3=\frac{30250×10×1}{100}

=₹3025

Amount 3=30250+3025=₹33275

Therefore,Bela should give back ₹33275 to the company after 1½ yrs.

_____________

P=Principal

R=Rate of interest

T=Time

Answered by Anonymous
143

⟾Given:

P=₹25000₹25000

R=20%p.a.=10% half Yearly be

T=1½years=3half years

⟾Tofind:

The amount of money that will clear her debt after 1½ yrs.

⟾Solution:

i}Interest 1= /{25000×10×1}{100}

100

25000×10×1

=₹2500₹2500

Amount 1=25000+2500=₹2750025000+2500=₹27500

ii} Interest 2=/{27500×10×1}{100}

100

27500×10×1

=₹2750₹2750

Amount 2=27500+2750=₹3025027500+2750=₹30250

iii} Interest 3={30250×10×1}{100}

100

30250×10×1

=₹3025₹3025

Amount 3=30250+3025=₹3327530250+3025=₹33275

Therefore,Bela should give back ₹33275₹33275 to the company after 1½ yrs.

_____________

P=Principal

R=Rate of interest

T=Time

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