Math, asked by AnanyaBaalveer, 2 days ago


  \boxed{ \huge \red \star\large  \green\star \small  \orange\star {\sf {Question}} \small \orange \star \large \green \star \huge  \red\star}
If the side of the chess board is smaller than it's perimeter by 42cm,find the area of the chess board.

Answers

Answered by XxPsychoticAngelxX
2

 \huge{ \red{ \mathfrak{ Solution}}}

14 \: as \: because \: 14 \times 3 = 56 \: which \: is \: 42 \: greater \: than \: 14 \: .

Answered by StarFighter
22

Answer:

Given :-

  • The side of the chessboard is smaller than it's perimeter by 42 cm.

To Find :-

  • What is the area of the chessboard.

Formula Used :-

\clubsuit Perimeter Of Square Formula :

\bigstar \: \: \sf\boxed{\bold{\pink{Perimeter_{(Square)} =\: 4 \times Side}}}\: \: \: \bigstar\\

\clubsuit Area Of Square Formula :

\bigstar \: \: \sf\boxed{\bold{\pink{Area_{(Square)} =\: Side \times Side}}}\: \: \: \bigstar\\

Solution :-

Let,

\mapsto \bf Side_{(Chessboard)} =\: x\: cm\\

Then, perimeter of a chessboard will be :

\small \implies \bf Perimeter_{(Chessboard)} =\: 4 \times Side\\

\implies \sf Perimeter_{(Chessboard)} =\: 4 \times x\: cm\\

\implies \sf\bold{\green{Perimeter_{(Chessboard)} =\: 4x\: cm}}\\

According to the question :

\bigstar The side of the chessboard is smaller than it's perimeter by 42 cm.

So,

\small \implies \bf Perimeter_{(Chessboard)} - Side_{(Chessboard)} =\: 42\\

\implies \sf 4x - x =\: 42

\implies \sf 3x =\: 42

\implies \sf x =\: \dfrac{\cancel{42}}{\cancel{3}}

\implies \sf x =\: \dfrac{14}{1}

\implies \sf\bold{\orange{x =\: 14}}\\

Hence, the side of a chessboard is :

\dashrightarrow \sf Side_{(Chessboard)} =\: x\: cm\\

\dashrightarrow \sf\bold{\blue{Side_{(Chessboard)} =\: 14\: cm}}\\

Now, we have to find the area of the chessboard :

Given :

  • Side = 14 cm

According to the question by using the formula we get,

\longrightarrow \bf Area_{(Chessboard)} =\: Side \times Side\\

\longrightarrow \sf Area_{(Chessboard)} =\: 14\: cm \times 14\: cm\\

\longrightarrow \sf\bold{\red{Area_{(Chessboard)} =\: 196\: cm^2}}\\

\sf\bold{\purple{\underline{\therefore\: The\: area\: of\: the\: chessboard\: is\: 196\: cm^2\: .}}}\\

\\

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