pls solve it now. (both of these que)
i'll mark ur sol as brainliest if it 'll be correct.
pls don't give a silly sol..for 10 marks...
_^_^___
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Mass of the block, m = 15 kg
Coefficient of static friction, μ = 0.18
Acceleration of the trolley, a = 0.5 m/s
As per Newton’s second law of motion, the force ( F ) on the block caused by the motion of the trolley is given by the relation:
F = ma = 15 × 0.5 = 7.5 N
so ans c is right 7.5N
Coefficient of static friction, μ = 0.18
Acceleration of the trolley, a = 0.5 m/s
As per Newton’s second law of motion, the force ( F ) on the block caused by the motion of the trolley is given by the relation:
F = ma = 15 × 0.5 = 7.5 N
so ans c is right 7.5N
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3
Solution Is attached with in the given Image ,Hope It will helps you !
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