Question

${\boxed {\LARGE{\mathfrak {Question:-}}}}$


In a electrical line having potential difference of 220Volts,a bulb is connected. if electric current of 0.5 Ampere is passing through the bulb then what is the power of the bulb?

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Answer 1

Potential Difference of supply line = 220 V

Current passing through the bulb = 0.5 A

We know,

• Power = V × Q or, V I t

Thus,

Power of Bulb = 220 × 0.5 × t

= 110 Watts

Answer 2

Given:

• Potential difference: 220V
• Current: 0.5 A

To calculate:

• Power

Solution:

We know that,

$\: \: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\qquad \longmapsto {{\purple{ P=VI}} } \\\end{gathered}$

here,

• P= Power
• V= Potential difference
• I= Current

So, subsituting the values,

$\large{ \green{P = 220 \times 0.5 = 110 \: Watt}}$

More to know,

Power: The rate at which electric energy is consumed by an object. This is also termed as electric power. The power"P" is given by

$\: \: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\qquad \longmapsto {{\purple{ P=VI}} } \\\end{gathered}$

Or

$\: \: \: \: \: \: \: \: \: \: \: \: \: \begin{gathered}\qquad \longmapsto {{\purple{ P= {I}^{2}R}} } \\\end{gathered}$

$\: \: \: \: \: \: \: \: \: \: \huge \bold{@WildCat7083 }$