Question

${\boxed {\LARGE{\mathfrak {solve\:it:-}}}}$

$\tt (3x^2-8)^2-23 (3x^2-8)+76=0$​

Answer 1

Steps using Quadratic formula:

$\: \: \: \: \: \: \: \large\ \pmb{\red{«\: คꈤ \mathfrak Sฬєя \: » }} (3x ^ { 2 } -8 ^ { 2 } )-23(3x ^ { 2 } -8)+76=0 \\ 3x^{2}-64-23\left(3x^{2}-8\right)+76=0 \\ 3x^{2}-64-69x^{2}+184+76=0 \\ -66x^{2}-64+184+76=0 \\ -66x^{2}+120+76=0 \\ -66x^{2}+196=0 \\ \\ x=\frac{0±\sqrt{0^{2}-4\left(-66\right)\times 196}}{2\left(-66\right)} \\ x=\frac{0±\sqrt{-4\left(-66\right)\times 196}}{2\left(-66\right)} \\ x=\frac{0±\sqrt{264\times 196}}{2\left(-66\right)} \\ x=\frac{0±\sqrt{51744}}{2\left(-66\right)} \\ x=\frac{0±28\sqrt{66}}{2\left(-66\right)} \\ x=\frac{0±28\sqrt{66}}{2\left(-66\right)} \\ x=-\frac{7\sqrt{66}}{33} \\ x=\frac{7\sqrt{66}}{33}$

$\: \: \: \: \: \: \: \: \: \: \huge \bold{@WildCat7083 }$

Answer 2

• Quadratic equations:

$\begin{gathered} \: \: \: \: \: \: \: \large\ \pmb{\red{«\: คꈤ \mathfrak Sฬєя \: » }} (3x ^ { 2 } -8 ^ { 2 } )-23(3x ^ { 2 } -8)+76=0 \\ 3x^{2}-64-23\left(3x^{2}-8\right)+76=0 \\ 3x^{2}-64-69x^{2}+184+76=0 \\ -66x^{2}-64+184+76=0 \\ -66x^{2}+120+76=0 \\ -66x^{2}+196=0 \\ \\ x=\frac{0±\sqrt{0^{2}-4\left(-66\right)\times 196}}{2\left(-66\right)} \\ x=\frac{0±\sqrt{-4\left(-66\right)\times 196}}{2\left(-66\right)} \\ x=\frac{0±\sqrt{264\times 196}}{2\left(-66\right)} \\ x=\frac{0±\sqrt{51744}}{2\left(-66\right)} \\ x=\frac{0±28\sqrt{66}}{2\left(-66\right)} \\ x=\frac{0±28\sqrt{66}}{2\left(-66\right)} \\ x=-\frac{7\sqrt{66}}{33} \\ x=\frac{7\sqrt{66}}{33} \end{gathered}$