Find the value of x^3 + y^3 + 9xy - 27 , when x + y = 3.
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Answered by
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x+y=3
cube both sides
(3)^3=(x+y)^3
27=x3+y3+3xy(x+y)
27=x3+y3+3xy(3)
27=x3+y3+9xy ......... (1)
x3+y3+9xy-27
from equation (1)
27-27
0
HOPE IT HELPS YOU
arjun6068:
if u want i will do it in paper and send u
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Hi buddy
Here is your answer
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