Question

$\boxed{\pmb{ \text{ \( \tt f: R \rightarrow R , f(x)=\left\{\begin{array}{lc} \tt2 x, & \tt x>3 \\ \tt x^{2}, & \tt 1<x \leq 3 \\ \tt 3 x, & \tt x \leq 1\end{array}\right. \) \: \: \: then \: find \: \: \: \( \tt f(-1)+f(2)+f(4) \)}}}$
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Answer 1

Answer:

f(-1) + f(2) + f(4)

==

For x<= 1 , function = 3x

Therefore , f(-1) = 3(-1) = -3

For 1<x<=3, function = x²

Therefore, f(2) = 2² = 4

For x>3 , function = 2x

Therefore, f(4) = 2(4) = 8

f(-1)+f(2)+f(4) = -3+4+8 = 9