Question

$\boxed{Question:-} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ if \: ∆+∆+©=420 \: and \: ©-∆=90, \\ then \: what \: is \: the \: value \: of \: ©? \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$
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Answer 1

Step-by-step explanation:

1. © = 90+ ∆
2. © = 90+ ∆∆+∆+90+∆ = 420
3. © = 90+ ∆∆+∆+90+∆ = 4203∆ = 420 -90
4. © = 90+ ∆∆+∆+90+∆ = 4203∆ = 420 -90∆ = 330/3
5. © = 90+ ∆∆+∆+90+∆ = 4203∆ = 420 -90∆ = 330/3∆= 110
7. © = 90+ ∆∆+∆+90+∆ = 4203∆ = 420 -90∆ = 330/3∆= 110 now put the value of ∆ to get the value of ©
8. © = 90+ ∆∆+∆+90+∆ = 4203∆ = 420 -90∆ = 330/3∆= 110 now put the value of ∆ to get the value of © © =90+∆
9. © = 90+ ∆∆+∆+90+∆ = 4203∆ = 420 -90∆ = 330/3∆= 110 now put the value of ∆ to get the value of © © =90+∆© = 90+ 110
10. © = 90+ ∆∆+∆+90+∆ = 4203∆ = 420 -90∆ = 330/3∆= 110 now put the value of ∆ to get the value of © © =90+∆© = 90+ 110© = 200

Answer 2

Answer:

Koi nhi Bhai

Kepler-452b is a super-Earth exoplanet orbiting within the inner edge of the habitable zone of the sunlike star Kepler-452 and is the only planet in the system discovered by Kepler. It is located about 1,800 light-years from Earth in the constellation of Cygnus.

Step-by-step explanation: