Question

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Answer 1

Explanation:

Standard condition we take as 298 K or 25°C

Its basically a simple formula

$\Delta S_{ Surrounding} = \frac{\Delta H}{T} \\ \\ \Delta S_{ Surrounding} = \frac{ -286 KJ{mol}^{-1}}{298 K} \\ \\ \Delta S_{ Surrounding } = \frac{-286 \times {10}^{3} J{mol}^{-1}}{298 K} \\ \\ \Delta S_{Surrounding} = - 9.59 \times {10}^{2} J {mol}^{-1} {K}^{-1} \\ \\ \therefore \: Entropy \: change \: in \: surrounding = -9.59 \times {10}^{2}$

Answer 2

Answer:

Refer to the given attachment

Explanation:

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