A tank is filled with water to a height of 12.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 9.4 cm. What is the refractive index of water? If
water is replaced by a liquid of refractive index 1.63 up to the same height, by what distance would the microscope have to be moved to focus on the needle again?
Answers
Explanation:
η=
9.4
12.5
=1.329
When the water is replaced by liquid of 1.63
η=
apparentdepth
12.5
1.63=
x
12.5
x=7.67
So Distance by which microscope have to be moved is 9.4−7.67=1.73cm
Apparent depth = real depth / refractive index
or
9.4 = 12.5 / μ
μ = 12.5 /9.4
μ = 1.33.
Now for the other part.
Apparent depth h' = 12.5 / μ'
h' = 12.5 /1.63
h' = 7.67
Previously apparent depth was 9.4 cm
Hence Microscope have to be moved by
= (9.4 - 7.67 )
= 1.73 cm
hope it's help u
Given :
❇ First case :
▪ Medium : water
▪ Real depth = 12.5cm
▪ Apparent depth = 9.4cm
❇ Second case :
▪ Medium : liquid
▪ Real depth = 12.5cm
▪ Refractive index of liquid = 1.63
To Find :
↗ Refractive index of water. (First case)
↗ Distance by which microscope have to be moved to focus on needle. (Second case)
Formula :
☞ Relation between refractive index of medium, real depth and apparent depth is given by
CalculaTion :
✴ First case :
✴ Second case :
☣ So, Distance by which microscope have to be moves is given by