Question

$\boxed{\sf{Find\:the\:17^{th}\:term\:of\:the\:AP:-}}$
ㅤㅤㅤ
★ㅤ$\sf{8 , 16 , 24 , 32 , 40 . . . . . . . \infty }$​

Answer 1

Answer:

136

Step-by-step explanation:

Here, First term = 8

Common Difference = (16-8)

= 8

Now the 17th Term of the AP

= a + (17-1)d

= a + (16)d

= 8 + (16)×8

= 8 + 128

= 136

Answer: 136

Answer 2

$\boxed{\sf{Question}}$

ㅤ$\sf{8 , 16 , 24 , 32 , 40 . . . . . . . \infty }$

$\boxed{\sf{Solution}}$

Here,

$\sf{a = 8}$

$\sf{d = 16-8}$

$\sf{d = 8}$

Using formula

$\boxed{\sf{an = a+(n-1)d}}$

$\sf{an =8+(n-1)8 }$

$\sf{an =8n+17-1×8 }$

$\sf{an =8n+16×8}$

an = 8+128

$\sf{an =136}$