Question

[tex]\boxed{\textbf{\large{Hello}}}

Q]⬇⬇⬇⬇⬇

y = secx - tanx

find (d^2y / dx^2 )​

Answer 1

Step-by-step explanation:

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Answer 2

y = secx - tanx

diffrenciating with respect to x we get

dy/dx = secx* tanx - sec^2x

again diffrenciating with respect to x we get

d^2y/dx^2 = secxtan^2x + sec^3x - 2sec^2xtanx

since using formula

dsec x/dx = secx tanx

dtanx/dx = sec^2x

d(x*y)/dx = y +( dy/dx )*x