Question

$calculate \: log_{2}( - {p}^{2} + 10p) = 4$

Answer 1

$hi \\ \\ formula \: \: log_{x}(y) = a \\ y = x {}^{a} \\ \\ \\ - p {}^{2} + 10p - 16 = 0 \\ \\ p {}^{2} - 10p + 16 = 0$