Question

$can \: ya \: all \: please \: help$
If 2sin(3x-15°)=√3, then find the value of sin²(2x+10°)+tan²(x+5°) .

Answer 1

sin(3x - 15°) =
$\: sin(3x - {15}^{o}) = \sqrt{3} \div 2$
sin (3x -15) = sin 60
3x = 90
x = 30
put this value and u will get the vaue

Answer 2

✨✨✨hope its helpful ✨✨✨