Question

$car \: accelerates \: from \: 6ms {}^{ - 1} \: 16ms^{ - 1} in \: 10 \: seconds. \: calculate \\ (a)acceleration \\ (b) \: distance \: covered \: by \: car \: in \: that \: time.$
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Answer 1

Step-by-step explanation:

I hope this answer helps you

Answer 2

Answer:

$acceleration \: = \frac{v - u}{t}$

$a \: = \frac{16 - 6}{10}$

$a \: = 1 \: \frac{m}{s {}^{2} }$

$v {}^{2} - u { }^{2} = 2as$

$256 - 36 = 2 \times 1 \times s$

$s = 110m$