Chemistry, asked by seenudhoni5399, 11 months ago

CH_3 - CH_2 - CH_2 - Cl \xrightarrow[KOH]{alc.} B \xrightarrow[]{HBr} C \xrightarrow[ether]{Na} D
In the above sequence of reactions, the product D is –
(a) propane
(b) 2, 3-dimethylbutane
(c) hexane
(d) allyl bromide

Answers

Answered by ssvijay738
0

(d) allyl bromide

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