Science, asked by thapaavinitika6765, 7 months ago

circumference\:x^2-6x+8y+y^2=0

solve

Answers

Answered by Anonymous
0

Answer:

x^2-6x+8y+y^2=0

x(x-6)+y(y+8)=0

Answered by Anonymous
1

\mathrm{Circle\:circumference\:given}\:x^2-6x+8y+y^2=0:\quad C=10\pi

\mathrm{Circle\:circumference}

C=2\pi r

\mathrm{Circle\:radius\:given}\:x^2-6x+8y+y^2=0:\quad r=5

C=2\pi 5

C=10\pi

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