Question

$class \: 10th \: \\ maths$
Help me to solve this question​

Answer 1

Answer:

Here you go my friend, just ask if you didn't get that

Answer 2

Answer:

x=1/2 and y=1/3

Explanation:

x = 1/2 , y = 1/3

Solution:

Given Equations Reducible to a Pair of Linear Equations in two variables :

2/x + 3/y = 13 ----(1)

5/x - 4/y = -2 ------(2)

If we substitute 1/x = a and 1/y = b , we get the following pair of linear equations:

2a+3b=13 -----(3)

5a-4b = -2 -----(4)

Coefficients of b are 3 and 4 and

their LCM is 12 .

Using the elimination method .

Equation (3) × 4 8a+12b=52

Equation (4) × 3 15a-12b=-6

'b' terms have opposite sign , so we add the two equations.

23a = 46

=> a = 46/23

=> a = 2

Substitute the value of a in equation (3), we get

=> 2×2 +3b =13

=> 4 + 3b = 13

=> 3b = 13 - 4

=> 3b = 9

=> b = 9/3

=> b = 3

But 1/x = a = 2 => x = 1/2

1/y = b = 3 => y = 1/3