Question

$➪ \: \color{brown} \:{\underline{\boxed{\large{\rm{Question}}}}}$
☞︎︎︎ Calculate the volume strength of a hydrogen peroxide solution containing
$\bf\fbox\red{ 60.7g per l}\: of \: H\frac{}{2} \:O \frac{}{2}$
${\underline{\boxed{\large{\rm{60.7 g {l}^{ - 1} }}}}}$
______________________________
Precautions to be taken while attempting
✍︎ Try to give quality answers .
✍︎ Hand - Written Solutions are. preferable !!
____ Best Answer will be Brainliest____
​

Answer 1

Answer:

Balanced Equation:

2 H₂O₂ → 2 H₂O + O₂

Based on the above equation we can say that: 2 moles of H₂O₂ will give rise to 1 mole of O₂.

We also know that 1 mole of any substance gives 22.4 liters at Standard temperature and pressure (STP). Hence we get:

⇒ 2 moles of H₂O₂ gives 22.4 liters of O₂

Converting 2 moles into grams, we get:

⇒ 2 × ( ( 2 × 1 ) + ( 2 × 16 ) )

⇒ 2 × ( 2 + 32 ) = 2 × 34 = 68 g

⇒ Mass of 2 moles of H₂O₂ = 68 g

Therefore 68 g/L of H₂O₂ gives rise to 22.4 volumes of O₂. Now according to the question, the given mass is 60.7 g/L of H₂O₂. Hence we get:

⇒ 68 g/L : 22.4 vol :: 60.7 g/L : ? (x)

⇒ x = (22.4 × 60.7) / 68

⇒ x = 1359.68 / 68

⇒ x = 19.99 ≈ 20 volumes

Hence the volume strength of a 60.7 g/L solution of H₂O₂ is 20 volumes.

Answer 2

Hey how Did u know that I belong to Uttarakhand .

So u R Gadwali btw Hru & tnx for giving ur intro but u didn't tell me ur name & class .

U can edit ur previous answer n wait I ' M following u with my other two id' s if there is space in that id' s then u can answer there also

꧁ •「Iτs PαHα∂i ฿Øy here」• ꧂