Question

$\color{pink} \boxed{\bf{ \colorbox{lavenderblush}{ \color{black}{Question}}}}$

The area of a trapezium is 400 cm2, the distance between the parallel sides is 16 cm. If one of the parallel sides is 20 cm, find the length of the other side.​

Answer 1

Answer:

30 cm

Step-by-step explanation:

let the required no. be x

400 cm^2 = (sum of parallel sides) × 1/2 × height

= (20 cm +x) × 1/2 × 16cm (16÷2 = 8)

= (20 cm +x) × 8cm

= 160cm^2 + 8x cm

400 cm^2 - 160 cm^2 = 8x cm

240cm^2 = 8x cm

240cm^2 / 8cm = x

30 cm = x

Answer 2

Given :-

♦ The area of a trapezium is 400 cm².

♦ The distance between the parallel sides is

16 cm.

♦ One of the parallel sides is 20 cm.

To find :-

♦ The length of the other side.

Solution :-

Let the length of the other parallel side be X cm

One of the parallel sides = 20 cm

The distance between the parallel sides = 16 cm

We know that

Area of a trapezium is (1/2)h(a+b) sq.units

We have,

a = X cm

b = 20 cm

h = 16 cm

Area of the trapezium = (1/2)×16(X+20) cm²

=> Area = 8(X+20) cm²

According to the given problem

Area of the trapezium = 400 cm²

=> 8(X+20) = 400

=> X+20 = 400/8

=> X+20 = 50

=> X = 50-20

=> X = 30 cm

Therefore, The value of X = 30 cm

Answer :-

♦ The length of the other side is 30 cm

Used formulae:-

♦ Area of a trapezium is (1/2)h(a+b) sq.units

• a and b are the parallel sides.
• h is the distance between two parallel sides.