Math, asked by IIinnocentBachiII, 5 months ago


\color{red}\boxed{\colorbox{black}{Question:-}}
ᴛʜᴇ ᴍᴀʀᴋᴇᴅ ᴘʀɪᴄᴇ ᴏꜰ ᴀ ᴛᴠ ɪꜱ 18500. ᴀ ᴅᴇᴀʟᴇʀ ᴀʟʟᴏᴡꜱ ᴛᴡᴏ ꜱᴜᴄᴄᴇꜱꜱɪᴠᴇ ᴅɪꜱᴄᴏᴜɴᴛꜱ ᴏꜰ 20% ᴀɴᴅ 5%. ꜰᴏʀ ʜᴏᴡ ᴍᴜᴄʜ ɪꜱ ᴛʜᴇ ᴛᴠ ᴀᴠᴀɪʟᴀʙʟᴇ?


• ᴋɪɴᴅʟʏ ᴅᴏɴᴛ ꜱᴘᴀᴍ

Answers

Answered by rehashbaghel
0

Answer:

7)⁴×(3/7)⁴÷1/3^-5

-5 is the power

answer right

Answered by Anonymous
19

\large\sf\underline{Given\::}

  • Marked price of a TV = Rs 18500

  • \sf\:1^{st} discount applied on the TV = 20 %

  • \sf\:2^{nd} discount applied on the TV = 5 %

\large\sf\underline{To\:find\::}

  • Selling price of the TV

\large\sf\underline{Concept\::}

Here we are asked to calculate the Selling price of the TV after the discounts are applied. In order to do so we will first calculate the price of TV when the first discount i.e., 20% is applied . Then, we will find the price of TV when the second discount is applied

\large\sf\underline{Solution\::}

At first, we need to calculate the price of the TV after the first discount is applied .

That is we need to find 20% of 18500 .

\sf\:20\:percent\:of\:18500

\sf\implies\:\frac{20}{100} \times 18500

\sf\implies\:\frac{20}{1\cancel{00}} \times 185\cancel{00}

\sf\implies\:20 \times 185

\sf\implies\:Rs\:3700

So the price of the TV after the first discount is applied would be :

\sf\:Rs\:18500\:-\:Rs\:3700

\sf\implies\:Rs\:(18500\:-\:3700)

\bf\implies\:Rs\:14800

Now we need to apply the second discount to find the price at which the TV is available .

That is we need to calculate 5 % of 14800 .

\sf\:5\:percent\:of\:14800

\sf\implies\:\frac{5}{100} \times 14800

\sf\implies\:\frac{5}{1\cancel{00}} \times 148\cancel{00}

\sf\implies\:5 \times 148

\sf\implies\:Rs\:740

Lastly we need to subtract the discount value from the selling price with the 20% discount to get the price at which the TV is available .

\sf\:Rs\:14800\:-\:Rs\:740

\large{\mathfrak\red{\implies\:Rs\:14060}}

_________________________

\dag\:\underline{\sf Therefore\:the\:selling\:price\:of\:the\:TV\:is\:Rs\:14060}.

!! Hope it helps !!

Similar questions