Question

$\color{red}{Hallo!}$


The sum and product of the zeroes of a quadratic polynomial

p(x)=a^2+bx+c are -3 and -2 respectively.

Show that b+c=5a​

Answer 1

HERE'S YOUR ANSWER,

Sum of zeroes,

$\alpha + \beta = - b \div a$

-3/1 =-b/a

$\alpha \beta = c \div a$

2/1=c/a

Therefore,

a=1

b=3

c=2

To prove,

b+c=5a

THEREFORE,

3+2=5×1

5=5

HENCE PROVED ✔️

HOPE THIS HELP YOU ❤️

THANK YOU ❤️

Answer 2

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