My question:
Total area of quadrilateral ABCD is 20 cm² and offsets on BD are 2 cm and 3 cm. The length of BD is
i) 5 cm ii) 6 cm iii) 8 cm
iv) 10 cm
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Answer : (!!!) 8
Area of the quadilateral = 20cm2
Area formula of this quadilateral = 1/2 × d × {h1 + h2}
Area = 1/2 × d ×(h1 + h2 )
20 = 1/2 × D × { 2 + 3 }
20 = 1/2 × D × {5}
D = 20 × 2 / 5
D = 40/5
D = 8
Hence BD = 8
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