Question

$Compare. \:$
The mass of an electron which is 9.11 × 10^-31 kg with the mass of a proton which is 1.673 × 10^-27....

$Question \: number \: 4. \:$
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with explanation

Answer 1

Hello Bro !

I am here to help you out !

Comparing means to take ratio and that's all is a piece of cake !

$\huge \pink \bigstar \: \: \green{ \dfrac{ \sf{mass \: of \: electron}} \red{ \sf{mass \: of \: proton}} } \\ \\ = \: \dfrac{9.11 × 10^{-31}}{1.673 × 10^{-21}} \\ \\ = \dfrac{9.11 \times {10}^{ - 31 - ( - 21)} }{1.673} \\ \\ = \dfrac{9.11 \times {10}^{ - 10} }{1.673} \\ \\ = \: \blue{\boxed{ \purple{ \underline{{\orange{ \bf{5.4 \: \times \: {10}^{ - 10} }}}}}}}$

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Answer 2

Answer:

Electron is 1827 tines lighter than proton.

Step-by-step explanation:

Comparing means to find the ratio of their masses.

Given

$m_{e} = 9.11 \times {10}^{ - 31} kg \\ m_{p} = 1.672 \times {10}^{ - 27} kg$

So, the ratio of their masses is

$\frac{ m_{e} }{ m_{p}} = \frac{9.11 \times {10}^{ - 31} kg}{1.672 \times {10}^{ - 27}kg } = \frac{1}{1837}$

This means that the electron is 1837 times lighter than the proton.

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