Question

$Consider \: the \: numbers \: 4", where \\ \: n \: is \: a \: natural \: number. \\ \: Check \: whether \: there \: is \\ \: any \: value \: of \: n \: for \: which \\ \: 4 {}^{n} \: ends \: with \: the \: digit \: zero.$
Please Solve this question with explanation..

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Answer 1

Step-by-step explanation:

The number ends with zero must have 2 and 5 as their prime factor.

whereas 4^n = (2×2)^n

it does not have 5 as a prime factor

so, it does not ends with zero

Therefore 4 cannot ends with number zero for any natural number n.

HOPE IT HELPS U..

Answer 2

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