Question

$\cos{ - 1}^{} \frac{x {}^{ 2} - 1 }{x {}^{2} + 1 } + \tan{ - 1}^{} \frac{2x}{x {}^{2} - 1} = \frac{2\pi}{3}$
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Answer 1

Answer:

d o no t know the answer bro