Question

$cos ^{2} a \: + \: sin \: a \: + \: cos \: a \: + \: tan ^{2} a \: = \: 2(sin \: a \times cos \: a)$
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Answer 1

Answer:

Hence, the given system of equations will have no solution, if k=2.

Answer 2

Answer:

$Prove: 1+cot2θ=csc2θ1+cot2θ=csc2θ</p><p></p><p>1+cot2θ=(1+cos2θsin2θ)Rewrite the left side. =(sin2θsin2θ)+(cos2θsin2θ)Write both terms with the common denominator. =sin2θ+cos2θsin2θ =1sin2θ =csc2θ1+cot2θ=(1+cos2θsin2θ)Rewrite the left \: side. =(sin2θsin2θ)+(cos2θsin2θ)Write \: both \: terms with \: the \: common \: denominator. =sin2θ+cos2θsin2θ =1sin2θ =csc2θ</p><p></p><p>Similarly, 1+tan2θ=sec2θ1+tan2θ=sec2θ</p><p></p><p>$