Question

$cos 28 \ sin62$
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Answer 1

Question correction:-

I think you have to divide the both trignometric ratios, orelse we won't get any particular value.

Question:-

Find value of :-

$\frac{cos28°}{sin62°}$

Formula to be used:-

cos(90°-θ) = sinθ

Solution :-

$= > \frac{cos28°}{sin62°} \\ = > \frac{cos(90° - 62°)}{sin62°} \\ = > \frac{sin62°}{sin62°} \\ = > 1$

Hence, your answer is 1.

Answer 2

Answer:

hope it's help youuuu...