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Answered by
47
Hola there,
cos45° = 1/√2
cos60° = 1/2
sin45° = 1/√2
sin60° = √3/2
So,
=> cos45° cos60° - sin45° sin60°
=> 1/√2×1/2 - 1/√2×√3/2
=> 1/2√2 - √3/2√2
=>(1 - √3)/2√2
Hope this helps...:)
cos45° = 1/√2
cos60° = 1/2
sin45° = 1/√2
sin60° = √3/2
So,
=> cos45° cos60° - sin45° sin60°
=> 1/√2×1/2 - 1/√2×√3/2
=> 1/2√2 - √3/2√2
=>(1 - √3)/2√2
Hope this helps...:)
PIYUSH2202:
sorry sissy but you committed a mistake so pls rectify it ^_^
Answered by
2
HEYA!!!
HERE IS YOUR ANSWER,
GIVEN : cos(45)cos(60) - sin(45)sin(60)
SOLUTION :
SINCE,
>> cos(45) = 1/√2
>> cos(60) = 1/2
>> sin(45) = 1/√2
>> sin(60) = √3/2
NOW SUBSTITUTING THE VALUES IN THE EQUATION,
=> (1/√2) × (1/2) - (1/√2) × (√3/2)
=> (1 ÷ 2√2) - (√3 ÷ 2√2)
=> (1 - √3) ÷ (2√2) (ANS)
HOPE IT HELPS YOU,
THANK YOU.
HERE IS YOUR ANSWER,
GIVEN : cos(45)cos(60) - sin(45)sin(60)
SOLUTION :
SINCE,
>> cos(45) = 1/√2
>> cos(60) = 1/2
>> sin(45) = 1/√2
>> sin(60) = √3/2
NOW SUBSTITUTING THE VALUES IN THE EQUATION,
=> (1/√2) × (1/2) - (1/√2) × (√3/2)
=> (1 ÷ 2√2) - (√3 ÷ 2√2)
=> (1 - √3) ÷ (2√2) (ANS)
HOPE IT HELPS YOU,
THANK YOU.
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