Math, asked by YuviUtsav, 6 months ago


 \cos(45) \div  \sec(30) +  \csc(30 )

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Answered by Anonymous
123

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 \Cos(45°) \div \sec(30) + \csc(30 )

\huge\tt{\boxed{\overbrace{\underbrace{\blue{Answer</p><p> }}}}}

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{ trigonometric values Is given :-

\boxed{\bold{Cos45° =  \frac{1}{ \sqrt{2} }}}

\boxed{\bold{Sec30 °=  \frac{2}{ \sqrt{3} }}}

\boxed{\bold{Cosec30° = 2}}

Now ,solving the main Question

⇛Cos45° \div Sec30° + Cosec30°

 ⇛ \frac{1}{ \sqrt{2} }  \div  \frac{2}{ \sqrt{3} }  + 2

 ⇛\frac{1}{ \sqrt{2} }  \times  \frac{ \sqrt{3} }{2}  + 2

  ⇛\frac{ \sqrt{3} }{2 \sqrt{2} }  + 2

⇛ \frac{ \sqrt{3} + 2(2 \sqrt{2} ) }{2 \sqrt{2} }  =  \frac{ \sqrt{3} + 4 \sqrt{2}  }{2 \sqrt{2} }

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