Math, asked by Anonymous, 7 months ago


 \cos(a)  -  \sin(a)  + 1  \div  \cos(a)  +  \sin(a)  - 1 =  cosec(a) +  \cot(a) . \\ using \: the \: identity \:  {cosec}^{2} (a)  = 1 +  {cot}^{2} (a)
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Answered by Anonymous
4

Answer:

LHS :

\sf :\implies \dfrac{\cos(a)  -  \sin(a)  + 1}{ \cos(a) +  \sin(a)   - 1} \\  \\  \\

\sf :\implies \dfrac{\cos(a)  - \sin(a)  + 1 }{\dfrac{\sin(a) }{ \dfrac{\cos(a) +  \sin(a)   - 1}{ \sin(a) }}} \qquad\Bigg\lgroup\textsf{\textbf{Dividing the Numerator and Denominator by $\sin$(a)}}\Bigg\rgroup \\  \\  \\

\sf :\implies \dfrac{\cot(a)  - 1 +  \cosec(a)}{ \cot(a) +1 -   \cosec(a)} \\  \\  \\

\sf :\implies\dfrac{\cot(a)+  \cosec(a) -  \bigg\{\cosec^{2} (a)  -  \cot^{2} (a) \bigg\}}{ \cot(a) +1 -   \cosec(a)} \\  \\  \\

\sf :\implies\dfrac{\cot(a)+  \cosec(a) -  \bigg\{\cosec (a)   +  \cot(a) \bigg\}\bigg\{\cosec (a)  -  \cot(a) \bigg\}}{ \cot(a) +1 -   \cosec(a)} \\  \\  \\

\sf :\implies\dfrac{\cot(a)+  \cosec(a) -  \bigg\{1 - \cosec(a)  -  \cot(a) \bigg\}}{ \cot(a) +1 -   \cosec(a)} \qquad\Bigg\lgroup\textsf{\textbf{Taking $\cot$(a) and $\cosec$(a) common}}\Bigg\rgroup\\  \\  \\

\sf  :\implies\cot(a)  +  \cosec(a)  \\  \\  \\

= RHS

Answered by Anonymous
8

Answer:

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A drinking glass is in the shape of a frustum of a cone height 14 cm . the diameters of its two circular ends are 4 cm and 2 cm . find the capacity of the glass.

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