Question

$cos2a + 2cos ^2a - 2cos2acosa \div sin2a - 2sin ^{2} asin2a$
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Answer 1

Step-by-step explanation:

I think the question is not written properly

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Answer 2

Step-by-step explanation:

[ cos2a + 2cos²2a - 2cos2acosa ] / [sin2a - 2sin²asin2a]

= [cos2a (1+2cos2a - 2cosa) ] / [sin2a(1-2sin²a) ]

= [cos2a(cos²a - 2cosa) ] / [sin2a(cos2a) ]

= [cos²a - 2cosa ] / sin2a

= [ cos²a - 2cosa ] / 2sinacosa

= (cos²a/2sinacosa) - (2cosa/2sinacosa)

= (1/2)cota - coseca