Question

$cosec^2$ θ $- cot^2$ θ = 1 Please Prove with a diagram

Answer 1

Answer:

38+4848+33838+203+39299+382828+29939+8282+8282+573+8838+4838

Answer 2

Answer:

Let ABC be an right angled triangle with B as right angle

Then

Cosecθ = AC / AB

Cotθ = BC / AB

We know that by Pythagorean Theorem

AB² + BC² = AC²

SO

Cosec² θ - Cot² θ

= (AC/AB) ² - (BC/AB)²

= (AC² - BC²) / ( AB)²

= AB² / AB²

= 1

Hence the proof follows

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