Question

$cosec {}^{2} theta - { \tan^2} {90 - theta }= { \sin}^{2} theta + \sin(90 - theta)$
pllz help its urgent....

Answer 1

HELLO DEAR,

we know that:-

tan(90-theta)=cot theta
and

(cosec ² theta-cot²theta)= 1

let THETA=alpha
${ \cosec}^{2} \alpha - { \tan}^{2} (90 - \alpha ) \\ = > ({ \cosec}^{2} \alpha - \cot^{2} \alpha ) = 1$
I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

tan(90-theta)=cot theta
and 

(cosec ² theta-cot²theta)= 1

let THETA=alpha
\begin{lgathered}{ \cosec}^{2} \alpha - { \tan}^{2} (90 - \alpha ) \\ = > ({ \cosec}^{2} \alpha - \cot^{2} \alpha ) = 1\end{lgathered}cosec2α−tan2(90−α)=>(cosec2α−cot2α)=1​ 

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