Question

$cosecx - 1 \div cotx =$

Answer 1

We know that,
sec²x - tan²x = 1
(secx-tanx)(secx+tanx) = 1
secx - tanx = 1/(secx+tanx)

(cosecx - 1)/cotx
cosecx/cotx - 1/cotx
1/cosx - 1/cotx
secx - tanx

So,
Your answer is 1/secx+tanx