Question

$cot+ tan= sec \times cos$
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Answer 1

$\cot \alpha + tan \alpha \\ = \frac{cos \alpha }{sin \alpha } + \frac{sin \alpha }{cos \alpha } \\ = \frac{{cos}^{2} \alpha + {sin}^{2} \alpha }{sin \alpha \times cos \alpha } \\ = \frac{1}{sin \alpha \times cos \alpha} \\ = cosec \alpha \times sec \alpha$

So the question has a small mistake.

Please correct the mistake in the question and you'll get the above answer on solving

HOPE IT HELPS!!