Math, asked by BacchuBHAU, 1 year ago


 \cot(theta) + 1
?

Answers

Answered by Anonymous
3
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Cot∅+1= 0

Cot∅= -1

cot∅= cot3π/4

∅= 3π/4 Or 135°



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Answered by Anonymous
0

 \cot( \alpha )  + 1 \\  =  \cot( \alpha )  =  - 1 \\  =  \cot( \alpha )  =  \cot( \binom{3\pi}{4} )  \\  =  \alpha  =  \frac{3\pi}{4}
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