Question

$d(n) = \dfrac{5}{16} \left(2\right)^{n - 1}$
what is the 5th term in the sequence

Answer 1

Answer:

5

Step-by-step explanation:

$d(n) = \frac{5 }{16} \times (2)^{n - 1} \\ when \: n = 5 \\ d(5) = \frac{5}{16} \times {2}^{5 - 1} \\ = \frac{5}{ {2}^{4} } \times {2}^{4} \\ = 5$