Physics, asked by UniQueSoul, 10 months ago

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If the time period of simple pendulam is measured to be as T = (2.5 ± 1) s, then persentage error in the measurement is

A) 2%

B) 4%

C) 1%

D) 2.5%
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Thanks!☃️ :D

Answers

Answered by TheVenomGirl
28

AnSwer:

  • Percentage error in measurement is 4%.

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It is given that the time period of simple pendulam is measured to be as T = (2.5 ± 1) s.

We need to find the percentage error in the measurement.

According to the formula of measuring time,

Percentage error in measuring time :-

➔ΔT / T × 100

➔(0.1 / 2.5) × 100

4%

So,

Percentage error in measurement is 4%

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Hope it helps uh !❤

Answered by Blaezii
5

Option - B

Percentage error in measurement is 4%.

Explanation:

Given :

The time period of simple pendulum is measured to be as T = (2.5 ± 1) s.

To Find :

The percentage error in the measurement.

Solution :

What is the percentage error in the measurement ?

In short, Percent error is the relative error multiplied by 100.

We know that :

Percentage error in measuring time is given by,

ΔT / T × 100

⇒ (0.1 / 2.5) × 100

⇒ 4 %

Hence,

Percentage error in measurement is 4%

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