Question

$\dfrac{n}{(n-r!)}$, का मान निकालिए जब (i) $n = 6$, $r = 2$ (ii) $n = 9$, $r = 5$.

Answer 1

Answer:

Step-by-step explanation:

(i)   यदि    n   =  6  तथा   r  =  2  हो तो  

$\frac{n!}{(n-r)!} = \frac{6!}{(6-2)!} \\\\=\frac{6*5*4!}{4!} \\\\=30$

(ii)  यदि   n  =  9 तथा  r = 5 हो तो  

$\frac{n!}{(n-r)!} = \frac{9!}{(9-5)!} \\\\=\frac{9!}{4!} \\\\=\frac{9*8*7*6*5*4!}{4!} \\\\=9*8*7*6*5\\\\=15120$