Question

$\diamondsuit$ Query#


It is given that in a group of 3 students the probabilty that the 2 students have the same birthday is 0.008 .What is the probabilty that the students not having the same birthday?

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Answer 1

Answer:

Here probability of 2 students not heaving the same birthday = 0.008

Probability that 2 students have the same birthday = 1 - p(e)

= 1-0.008

= 0.992

Answer 2

Step-by-step explanation:

see the above mentioned attachment