Question

$\displaystyle\huge\red{\underline{\underline{QUESTION}}}$

Prove that the sum of squares of sides of a parallelogram is equal to the sum of the squares of it's diagonals.
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Answer 1

Answer:

Draw perpendiculars from C and D on AB as shown. Thus the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides

Answer 2

Step-by-step explanation:

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