Question

$\displaystyle\huge\red{\underline{\underline{QUESTION}}}$


★PROVE★

$\sqrt{ \frac{1 + \sin( \alpha ) }{1 - \sin( \alpha ) } } = tan \alpha + sec \alpha$
COPIED ANSWERS NOT ALLOWED ​

Answer 1

Answer:

srry dear I have problem with the connection

Answer 2

Answer:

To prove .

$\sqrt{ \frac{1 + \sin( \alpha ) }{1 - \sin( \alpha ) } } = tan \alpha + sec \alpha </p><p>$

1−sin(α)

1+sin(α)

=tanα+secα

(1 - Sin @/1+sina @)

(1- Sin @ )² (1-sin²@)

1+sin²A-2sinA/ cos²A

sec²A + tan² A - 2 tanA.secA

So , (sec @ - tan @)²

Square root of LHS = sec@ - tan@