Question

$\displaystyle\huge\red{\underline{\underline{QuEsTIoN}}}$

Using concept of quantum numbers, calculate the maximum number of Electrons present in the 'M 'shell.
Give thier distribution in shells and subshells and orbitals.​

Answer 1

Answer:

3rd shell has 18 electrons

Explanation:

M shell is a 3rd shell

so, 3s, 3p, 3d

3s has 1 orbital

3p has 3 orbital

3d has 5 orbital

((1 orbital has 2 electrons))

so,

3s has 2 electrons

3p has 6 electrons

3d has 10 electrons

so, Total Electrons in 3rd shell = 3s + 3p + 3d

total electrons = 2 + 6 + 10

total electrons = 18 electrons

Answer 2

$\sf\red{AnsWeR}$

$\tt{K,LM}$

$\tt{M \: = n = 1,2,3 }$

$\tt{N \: (Principal \: QN) = 3 }$

$\tt{Total \: No. \: of \: CO = QN²}$

$\tt{➥ 2× 3v3}$

$\tt{➥ 18CO²}$

$\tt{Dismabnm \: L = (n-1) }$

$\boxed{3s,3p,3d}$