Math, asked by Anonymous, 5 hours ago

\displaystyle \sf \lim_{n \to \infty} \bigg(  \sum \limits^{n + 9}_{k = 10}\frac{2^{11 \frac{k - 9}{n} } }{  \log_{2}e^{ \frac{n}{11} }   } -  \sum \limits_{k = 0}^{n - 1}   \frac{58}{\pi \sqrt{(n - k)(n + k)} } \bigg  )

Answers

Answered by sajan6491
13

 \bf \red{See  \: the \:  attachment}

Attachments:
Similar questions